MATH EQUATIONS 1. If (3x+4)2 +(3x-2)2=(6x+5)(3x-2)+12 then find the value of x 1. 2 2. 1 3. -3 4.-2 Solution:- (D) (3x+4)2 +(3x-2)2=(6x+5)(3x-2) + 12 → 9x2 + 24x+16 + 9x2 + 12x + 4 = 18x2 + 3x - 10 + 12 → 18x2 + 12x +20 = 18x2 +3x + 2 → 9x + 18 → x = -2 NOTE :- → You guys can see 9x2,18x2 → It Means 9 to the power of 2 2. The sum of numerator and denominator of a fraction is 11. If 1 is added to the numerator and 2 is subtracted from the denominator it becomes 2 by 3. Find the fraction. Solutions :- → Let the numerator = x → denominator = y According to question, → x + 1 / y + 1 = 2 / 3 → 3x + 3 = 2y + 2 → 3x - 2y = -1 ----------------1 → x - 1 / y - 1 = 3 / 5 → 5x - 5 = 3y - 3 → 5x - 3y =2 ------------------2 We get 2 question , Now by Elimination Method , → 3x - 2y = -1 × 5 → 5x - 3y = 2 × 3 → 15x - 10y = -5 → 15x - 9y = 6 → -y = -11 → y = 11 Now put the value of i...